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Stationary waves in a closed pipe (odd harmonics only)

A pipe closed at one end has a displacement node at the closed end and a displacement antinode at the open end, so L = (2n − 1)λ/4. This gives λ = 4L/(2n − 1) and f = (2n − 1)v/4L, so only the odd harmonics exist (f₁, 3f₁, 5f₁ …). The fundamental is λ = 4L, exactly one octave below an open pipe of the same length.

λ = 4L/(2n − 1) · f = (2n − 1) v/(4L) · odd harmonics only

What this actually means

The odd-only result is not a rule to memorise, it is forced by the geometry. You need a node at one end and an antinode at the other, and the shortest such pattern is a quarter of a wavelength. Every extra half wavelength you add keeps the pattern legal, hence quarter, three-quarters, five-quarters and so on.

So there is no second harmonic and no fourth harmonic in a closed pipe. If a question offers you a frequency of exactly 2f₁ for a closed pipe, it is wrong.

Careful with overtone numbering: the first overtone of a closed pipe is the third harmonic, at 3f₁, not 2f₁. This is the single most common closed-pipe mistake.

A closed pipe of length L sounds an octave lower than an open pipe of the same length, because 4L is twice 2L. That is why closing off a pipe on a wind instrument drops the pitch so dramatically.

For sound, the closed end is a displacement node but a pressure antinode, which is why the pressure variation is largest exactly where the air is not moving.

The trap

Calling the first overtone of a closed pipe the second harmonic at 2f₁, when it is the third harmonic at 3f₁.

Prove it — watch it be true

  1. Select the 3D closed pipe and set the mode selector to n = 1, confirming a node at the closed end and an antinode at the open end.
  2. Try to select the even harmonics and confirm the mode selector skips them as impossible.
  3. Step to the next available mode and confirm it is the third harmonic at 3f₁, with λ = 4L/3.
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